look at why that is. When you send a task message in Celery, that message won’t contain any source code, but only the name of the task you want to execute. This works similarly to how host names work on project already using these patterns extensively and you don’t have the time to refactor the existing code then you can consider specifying the names explicitly instead of relying on the automatic naming: exc: raise self.retry(exc=exc) Note The app.Task.retry() call will raise an exception so any code after the retry won’t be reached. This is the Retry exception, it isn’t handled as an error but rather

look at why that is. When you send a task message in Celery, that message won’t contain any source code, but only the name of the task you want to execute. This works similarly to how host names work on project already using these patterns extensively and you don’t have the time to refactor the existing code then you can consider specifying the names explicitly instead of relying on the automatic naming: exc: raise self.retry(exc=exc) Note The app.Task.retry() call will raise an exception so any code after the retry won’t be reached. This is the Retry exception, it isn’t handled as an error but rather

look at why that is. When you send a task message in Celery, that message won’t contain any source code, but only the name of the task you want to execute. This works similarly to how host names work on project already using these patterns extensively and you don’t have the time to refactor the existing code then you can consider specifying the names explicitly instead of relying on the automatic naming: exc: raise self.retry(exc=exc) Note The app.Task.retry() call will raise an exception so any code after the retry won’t be reached. This is the Retry exception, it isn’t handled as an error but rather

look at why that is. When you send a task message in Celery, that message won’t contain any source code, but only the name of the task you want to execute. This works similarly to how host names work on project already using these patterns extensively and you don’t have the time to refactor the existing code then you can consider specifying the names explicitly instead of relying on the automatic naming: exc: raise self.retry(exc=exc) Note The app.Task.retry() call will raise an exception so any code after the retry won’t be reached. This is the Retry exception, it isn’t handled as an error but rather

look at why that is. When you send a task message in Celery, that message won’t contain any source code, but only the name of the task you want to execute. This works similarly to how host names work on project already using these patterns extensively and you don’t have the time to refactor the existing code then you can consider specifying the names explicitly instead of relying on the automatic naming: exc: raise self.retry(exc=exc) Note The app.Task.retry() call will raise an exception so any code after the retry won’t be reached. This is the Retry exception, it isn’t handled as an error but rather

look at why that is. When you send a task message in Celery, that message won’t contain any source code, but only the name of the task you want to execute. This works similarly to how host names work on project already using these patterns extensively and you don’t have the time to refactor the existing code then you can consider specifying the names explicitly instead of relying on the automatic naming: exc: raise self.retry(exc=exc) Note The app.Task.retry() call will raise an exception so any code after the retry won’t be reached. This is the Retry exception, it isn’t handled as an error but rather

look at why that is. When you send a task message in Celery, that message won’t contain any source code, but only the name of the task you want to execute. This works similarly to how host names work on project already using these patterns extensively and you don’t have the time to refactor the existing code then you can consider specifying the names explicitly instead of relying on the automatic naming: Celery Documentation, Release 4.0.0 Note: The app.Task.retry() call will raise an exception so any code after the retry won’t be reached. This is the Retry exception, it isn’t handled as an error but rather

look at why that is. When you send a task message in Celery, that message won’t contain any source code, but only the name of the task you want to execute. This works similarly to how host names work on project already using these patterns extensively and you don’t have the time to refactor the existing code then you can consider specifying the names explicitly instead of relying on the automatic naming: exc: raise self.retry(exc=exc) Note The app.Task.retry() call will raise an exception so any code after the retry won’t be reached. This is the Retry exception, it isn’t handled as an error but rather

look at why that is. When you send a task message in Celery, that message won’t contain any source code, but only the name of the task you want to execute. This works similarly to how host names work on project already using these patterns extensively and you don’t have the time to refactor the existing code then you can consider specifying the names explicitly instead of relying on the automatic naming: exc: raise self.retry(exc=exc) Note The app.Task.retry() call will raise an exception so any code after the retry won’t be reached. This is the Retry exception, it isn’t handled as an error but rather

look at why that is. When you send a task message in Celery, that message won’t contain any source code, but only the name of the task you want to execute. This works similarly to how host names work on project already using these patterns extensively and you don’t have the time to refactor the existing code then you can consider specifying the names explicitly instead of relying on the automatic naming: as exc: raise self.retry(exc=exc) Note: The app.Task.retry() call will raise an exception so any code after the retry won’t be reached. This is the Retry exception, it isn’t handled as an error but rather